Question

optical power of 1 mw is launched into an optical fiber of length 100 m. if the power emerging from the other end is 0.6 mw, calculate the fiber attenuation.

Answer 1

The fiber attenuation is calculated using the ratio of input power to output power in a logarithmic scale. For an optical power input of 1 mW and output of 0.6 mW in a fiber of 100 m, the attenuation is approximately 2.219 dB.

Step-by-step explanation:

To calculate the fiber attenuation in dB, we can use the formula:

Attenuation (dB) = 10 * log10(Pin/Pout)

Where Pin is the input power and Pout is the output power.

Given that the optical power launched into the fiber is 1 mW (milliwatt) and the power emerging is 0.6 mW, we can plug these values into the formula:

Attenuation (dB) = 10 * log10(1 mW / 0.6 mW)

Attenuation (dB) = 10 * log10(1/0.6)

Attenuation (dB) = 10 * log10(1.6667)

Attenuation (dB) ≈ 10 * 0.2219

Attenuation (dB) ≈ 2.219 dB

Therefore, the attenuation of the fiber is approximately 2.219 dB for the 100 m length.