Final answer:
The weight of two moles of the organic compound obtained by heating sodium ethanoate with sodium hydroxide in the presence of calcium oxide is 164.00 g.
Step-by-step explanation:
In order to find the weight of two moles of the organic compound, we need to calculate the molar mass of the compound and then multiply it by 2. The organic compound is obtained by heating sodium ethanoate with sodium hydroxide in the presence of calcium oxide.
The molecular formula for sodium ethanoate is CH3COONa, and the molar mass of sodium ethanoate is calculated as follows:
Molar mass of Na (22.99 g/mol) + Molar mass of C (12.01 g/mol) + Molar mass of H (1.01 g/mol) + Molar mass of O (16.00 g/mol) + Molar mass of O (16.00 g/mol) + Molar mass of Na (22.99 g/mol) = 82.00 g/mol
Therefore, the weight of two moles of the organic compound is 82.00 g/mol * 2 = 164.00 g