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What is the ph of a buffer solution prepared by mixing equal volumes of 0.3 m in tris in the acid form and 0.15 m in tris in the basic form?

a. 6.55
b. 8.00
c. 7.25
d. 7.60

1 Answer

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Final answer:

The pH of the buffer solution prepared by mixing equal volumes of 0.3 M Tris in the acid form and 0.15 M Tris in the basic form is 7.6, indicating a slightly basic solution.

Step-by-step explanation:

The pH of a buffer solution prepared by mixing equal volumes of 0.3 M Tris in the acid form (TrisH+ or TrisHCl) and 0.15 M Tris in the basic form (Tris or Tris base) can be calculated using the Henderson-Hasselbalch equation:

pH = pKa + log ([Tris base]/[TrisH+])

Since equal volumes of 0.3 M TrisH+ and 0.15 M Tris base are mixed, the concentration of Tris base will be halved due to dilution. The final concentrations of TrisH+ and Tris base in the solution will be:

  • [TrisH+] = 0.3 M
  • [Tris base] = 0.075 M (after dilution)

Now, we apply these concentrations to the Henderson-Hasselbalch equation using the pKa value for Tris, which is 8.1:

pH = 8.1 + log (0.075/0.3)

The calculated pH of the buffer solution is therefore 7.6, which indicates that the solution is somewhat basic, as the pH is slightly below the pKa value of Tris.

User Mark Longmire
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