Question

if one peak sun is equal to 1000 w/m², what is the input power to a solar cell with dimensions of 41 cm x 41 cm under one sun illumination? enter your answer to the nearest tenth of a watt.

Answer 1

The input power to a solar cell of dimensions 41 cm x 41 cm under one sun illumination is 168.1 W, after converting the area to square meters and multiplying by the intensity of one peak sun which is 1000 W/m².

Step-by-step explanation:

To calculate the input power to a solar cell under one sun illumination, we consider the intensity of sunlight as 1000 W/m² (one peak sun). To find the power received by the solar cell, we must multiply this intensity by the area of the solar cell. The dimensions of the solar cell are 41 cm x 41 cm, which needs to be converted to square meters (m²) for the calculation to be consistent.

Firstly, convert the dimensions to meters:

• 41 cm = 0.41 meters

Next, calculate the area of the solar cell in square meters:

• Area = length × width = 0.41 m × 0.41 m = 0.1681 m²

Finally, calculate the input power:

• Power = intensity × area = 1000 W/m² × 0.1681 m² = 168.1 W

Therefore, the input power to the solar cell under one sun illumination is 168.1 W, to the nearest tenth of a watt.