Question

Two liters, L, of 0.125 M solution are prepared from 0.050 L of a stock solution. What was the concentration of the initial stock solution?

Answer 1

To find the concentration of the initial stock solution, use the dilution equation C1V1 = C2V2. With the values provided (C2 = 0.125 M, V2 = 2 L, V1 = 0.050 L), the concentration (C1) of the initial solution can be calculated accordingly.

Step-by-step explanation:

To calculate the concentration of the initial stock solution, we use the dilution equation C1V1 = C2V2, where C1 is the stock concentration, V1 is the volume of the stock solution, C2 is the diluted concentration, and V2 is the volume of the final solution. In this scenario, we are given C2 as 0.125 M and V2 as 2 liters. V1 is given as 0.050 L. The task is to find C1.

Using the provided values, the equation becomes (C1)(0.050 L) = (0.125 M)(2 L). To solve for C1, we would perform the following calculation: C1 = (0.125 M * 2 L) / 0.050 L, resulting in C1 being the concentration of the initial stock solution.