231k views
5 votes
approximately how much work is required to move a -5 c point charge 1 m in a 30 v/m uniform electric field towards a positive source?

1 Answer

3 votes

Final answer:

Approximately -150 joules of work is required to move a -5 C point charge 1 m in a 30 V/m uniform electric field towards a positive source. This work is done by the electric force.

Step-by-step explanation:

The question pertains to the concept of work done on a charge in an electric field, which is a fundamental topic in Physics. Work done (W) in moving a charge (q) through an electric potential (V) is calculated by the equation W = qV. Given the charge is -5 C (coulombs) and the electric field (E) is 30 V/m (volts per meter), and the charge is moved 1 m towards a positive source, the potential difference (V) is E × distance, which equals 30 V/m × 1 m = 30 V.

Work done to move the charge is then calculated by multiplying the charge by the potential difference. W = (-5 C) × (30 V) = -150 J (joules). The negative sign indicates that work is done by the electric force, not by an external agent.

User Hrickards
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.