Final answer:
Approximately -150 joules of work is required to move a -5 C point charge 1 m in a 30 V/m uniform electric field towards a positive source. This work is done by the electric force.
Step-by-step explanation:
The question pertains to the concept of work done on a charge in an electric field, which is a fundamental topic in Physics. Work done (W) in moving a charge (q) through an electric potential (V) is calculated by the equation W = qV. Given the charge is -5 C (coulombs) and the electric field (E) is 30 V/m (volts per meter), and the charge is moved 1 m towards a positive source, the potential difference (V) is E × distance, which equals 30 V/m × 1 m = 30 V.
Work done to move the charge is then calculated by multiplying the charge by the potential difference. W = (-5 C) × (30 V) = -150 J (joules). The negative sign indicates that work is done by the electric force, not by an external agent.