Question

the proper tangential speed for machining cast iron is about 0.560 m/s . at how many revolutions per minute should a piece of stock 0.0800 m in diameter be rotated in a lathe to produce this tangential speed?

Answer 1

To produce a tangential speed of 0.560 m/s, a piece of stock with a diameter of 0.0800 m should be rotated at approximately 26.602 revolutions per minute in a lathe.

Step-by-step explanation:

To find the number of revolutions per minute (rpm) at which a piece of stock should be rotated in a lathe to produce a tangential speed, we can use the formula:

tangential speed = (2 * pi * radius * rpm) / 60

Given: tangential speed = 0.560 m/s and diameter = 0.0800 m

First, we need to find the radius by dividing the diameter by 2: 0.0800 m / 2 = 0.0400 m

Substituting the values into the formula, we get:

0.560 m/s = (2 * pi * 0.0400 m * rpm) / 60

Simplifying the equation:

rpm = (0.560 m/s * 60) / (2 * pi * 0.0400 m)

rpm = 26.602 revolutions per minute