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When a 0.66g sample of olive oil is burned in a calorimeter, the heat released increases the temperature of 370g of water from 22.7°C to 38.8°C. What is the energy value for the olive oil in kJ/g and kCal/g?

User Grammin
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The energy value of the olive oil is approximately 37763.77 kJ/g and 9025.76 kCal/g.

Here's how to calculate the energy value of the olive oil in kJ/g and kCal/g:

1. Calculate the heat released by the olive oil:

Define the specific heat capacity of water (c_water) as 4.184 J/g°C.

Calculate the temperature change of the water (ΔT_water) as 38.8°C - 22.7°C = 16.1°C.

Calculate the heat absorbed by the water (Q_water) using the formula: Q_water = m_water * c_water * ΔT_water

Q_water = 370 g * 4.184 J/g°C * 16.1°C ≈ 25178 J

2. Assume the heat released by the olive oil is equal to the heat absorbed by the water.

This assumption holds true under ideal conditions in a calorimeter. Therefore, the heat released by the olive oil (Q_olive_oil) is also 25178 J.

3. Calculate the energy value per gram of olive oil:

Divide the heat released by the olive oil by its mass: E_value (kJ/g) = Q_olive_oil / m_olive_oil

E_value (kJ/g) = 25178 J / 0.66 g ≈ 37763.77 kJ/g

4. Convert the energy value to kCal/g:

1 kcal is equal to 4.184 kJ. Therefore, E_value (kCal/g) = E_value (kJ/g) / 4.184

E_value (kCal/g) ≈ 37763.77 kJ/g * (1 kcal/4.184 kJ) ≈ 9025.76 kCal/g

Therefore, the energy value of the olive oil is approximately 37763.77 kJ/g and 9025.76 kCal/g.

User DecentGradient
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