Question

For the reaction 2Li(s)+F2 (g) → 2LiF(s) identify the limiting reactant for each of the initial quantities of reactants. Drag the appropriate items to their respective bins.

Items:
2.85X10³ gLi
6.79X10³ gF2
10.5gLi
37.2gF2
1.0gLi
1.0gF2
Li is the limiting reagent F2 is the limiting reagent

Answer 1

The limiting reactant is determined by calculating which reactant produces the lesser amount of product using the stoichiometric ratios from the balanced equation. This involves converting masses of reactants to moles and then comparing the potential product amounts.

Step-by-step explanation:

To determine the limiting reactant in the reaction 2Li(s) + F₂(g) → 2LiF(s), you must first calculate the amount of product that can be produced from each provided quantity of reactant. Whichever reactant yields the lesser amount of product is the limiting reactant. This can be calculated using stoichiometric ratios from the balanced chemical equation. For example, if we have 2.85x10³ g Li and 6.79x10³ g F₂, we first convert these mass quantities to moles and then use the molar ratio from the balanced equation to see which will yield less product.

For instance:

• Calculate moles of Li:
• Calculate moles of F₂:
• Compare moles of product formed from moles of each reactant using stoichiometry

This approach can be applied to each set of initial reactant quantities to identify the limiting reactant for each situation.