Final answer:
The distance between the points -2-3i and 3+9i in the complex plane is 13 units.
Step-by-step explanation:
The distance between two points in the complex plane is calculated using the distance formula.
Let's consider the points -2-3i and 3+9i.
The distance formula is given by:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
where (x1, y1) and (x2, y2) are the coordinates of the two points.
Substituting the values:
d = sqrt((3 - (-2))^2 + (9 - (-3))^2)
Simplifying further:
d = sqrt(5^2 + 12^2)
d = sqrt(25 + 144)
d = sqrt(169)
d = 13
Therefore, the distance between -2-3i and 3+9i is 13.