Question

PCl₅ (g) PCl₃(g) + Cl₂(g) In above reaction at equilibrium condition mole fraction of the PCl₅ is 0.4 and mole fraction of the Cl₂ is 0.3, then find out mole fraction of the PCl₃.

Answer 1

To determine the mole fraction of PCl₃ at equilibrium when the mole fractions of PCl₅ and Cl₂ are given, subtract their sum from 1. The calculation reveals that the mole fraction of PCl₃ is 0.3.

Step-by-step explanation:

The student is asking about the equilibrium composition of a reaction in which phosphorus pentachloride (PCl₅) decomposes into phosphorus trichloride (PCl₃) and chlorine gas (Cl₂).

Given that the mole fraction of PCl₅ is 0.4 and the mole fraction of Cl₂ is 0.3 at equilibrium, we need to calculate the mole fraction of PCl₃.

Mole fractions in a mixture must add up to 1, so to find the mole fraction of PCl₃, we subtract the sum of the mole fractions of PCl₅ and Cl₂ from 1:

Mole fraction of PCl₃ = 1 - (Mole fraction of PCl₅ + Mole fraction of Cl₂)

= 1 - (0.4 + 0.3)

= 0.3

Therefore, the mole fraction of PCl₃ is also 0.3.