Final answer:
To find the number of Triclosan molecules in a 200 mL hand sanitizer bottle with 0.2% w/v, you calculate the mass, convert to moles, and then multiply by Avogadro's Number. The result is approximately 8.318 × 10²⁰ Triclosan molecules, which is not aligned with the provided answer choices, indicating a possible error in the question.
Step-by-step explanation:
The student has asked about the number of Triclosan molecules in a 200 mL hand sanitizer bottle claiming to contain 0.2% w/v Triclosan. First, to find the mass of Triclosan in the solution, multiply the volume of the solution by the percentage concentration (in grams per volume), which gives 200 mL * 0.2 g/100 mL = 0.4 g Triclosan.
Next, we need to calculate the number of moles of Triclosan using its molecular weight. Assuming the molecular weight of Triclosan is approximately 289.54 g/mol (C₁₂H₇Cl₃O₂), the number of moles will be mass/molecular weight which is 0.4 g / 289.54 g/mol ≈ 0.001381 moles.
Finally, to calculate the number of molecules of Triclosan, we multiply the number of moles by Avogadro's Number (approximately 6.022 × 10²³ molecules/mol). So, the calculation is 0.001381 moles * 6.022 × 10²³ molecules/mol ≈ 8.318 × 10²⁰ molecules.
Therefore, the number of Triclosan molecules in the sanitizer is approximately 8.318 × 10²⁰, which is not one of the provided answer choices. Thus, there may be a miscalculation or typo in the question's given answer options.