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Triclosan (CH.Cl:02) is an antibacterial and antifungal agent. It is a polychloro phenoxy phenol. It is widely used as a preservative and antimicrobial agent in personal care products such as soaps, skin creams, and deodorants etc. A label on a 200 mL hand sanitizer bottle claims that it contain Triclosan 0.2% w/v. What will be the number of molecules of Triclosan present in the bottle? (NAis Avogadro's Number)

(a) 1.4 X 1025 NA
(b) 1.4 X 1024 NA
(c) 1.4 X 1023 NA
(d) 1.4 X 1022 NA​

1 Answer

1 vote

Final answer:

To find the number of Triclosan molecules in a 200 mL hand sanitizer bottle with 0.2% w/v, you calculate the mass, convert to moles, and then multiply by Avogadro's Number. The result is approximately 8.318 × 10²⁰ Triclosan molecules, which is not aligned with the provided answer choices, indicating a possible error in the question.

Step-by-step explanation:

The student has asked about the number of Triclosan molecules in a 200 mL hand sanitizer bottle claiming to contain 0.2% w/v Triclosan. First, to find the mass of Triclosan in the solution, multiply the volume of the solution by the percentage concentration (in grams per volume), which gives 200 mL * 0.2 g/100 mL = 0.4 g Triclosan.

Next, we need to calculate the number of moles of Triclosan using its molecular weight. Assuming the molecular weight of Triclosan is approximately 289.54 g/mol (C₁₂H₇Cl₃O₂), the number of moles will be mass/molecular weight which is 0.4 g / 289.54 g/mol ≈ 0.001381 moles.

Finally, to calculate the number of molecules of Triclosan, we multiply the number of moles by Avogadro's Number (approximately 6.022 × 10²³ molecules/mol). So, the calculation is 0.001381 moles * 6.022 × 10²³ molecules/mol ≈ 8.318 × 10²⁰ molecules.

Therefore, the number of Triclosan molecules in the sanitizer is approximately 8.318 × 10²⁰, which is not one of the provided answer choices. Thus, there may be a miscalculation or typo in the question's given answer options.

User William Brawner
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