Question

A block of mass 500 m the area of cross section of wire is 10 mm square when the load is removed the wire contract with 0.5 cm young's modulus of the material of wire will be

a. 10×10¹⁴ N/m²
b. 4×10¹⁴ N/m²
c. 8×10¹¹ N/m²
d. 7×10¹⁰ N/m²

Answer 1

The young's modulus of the material of wire will be
`7 * 10^{10`

How to get the young modulus of the material

The young Modulus of a material is defined as the stiffness of a given material. It can be described as the stress that a property would get in response to the strain that it receives

The formula is given as

Force * load / Δ in load * A

We have to first solve for the strain then we solve for the stress

wire contract / length of wire

`(0.5 * 10^(-2))/(70 * 10^(-2))`

= 1 / 140

We have to solve for the stress next

stress = 500 x 10 = 5000

5000/ 10 * 10⁻⁶

= 500 x 10⁶

Young modulus = stress / strain

=
`((500 * 10^6))/((1 / 140))`

= 500000000 / 0.007142857

= 70,000,000,420

=
`7 * 10^{10`

The young's modulus of the material of wire will be
`7 * 10^{10`

Complete question

A block of mass 500kg is suspended by wire of length 70 cm. The area of cross-section of wire is 10mm square. When the load is removed, the wire contracts by 0.5cm. The young's modulus of the material of wire will be