Final answer:
Object A, with a temperature increase of 30°C, has a higher specific heat capacity than object B, which increased by 50°C when equal heat is given to both. Object A's specific heat is 5/3 times that of object B.
Step-by-step explanation:
The question is related to the concept of specific heat in Physics. When equal amounts of heat are given to two objects of the same mass but their temperatures increase by different amounts, the object with the smaller temperature change has a higher specific heat capacity. The heat energy absorbed or released by an object when it changes temperature is given by the formula Q = mcΔT, where Q is the heat absorbed/released, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
For object A, the temperature increase is 30°C, and for object B, it's 50°C. Since the same amount of heat Q is given to both and they have the same mass m, we can say that the specific heat capacity (c) is inversely proportional to the temperature change (ΔT). Hence, object A with the 30°C increase has a higher specific heat capacity than object B, which has a 50°C increase. To find the factor by which object A's specific heat is more than B's, we can set up the ratio of their temperature changes B's ΔT / A's ΔT = 50°C / 30°C = 5/3. Therefore, object A has a specific heat 5/3 times that of object B.