Question

a boy who has an initial velocity of 2 m/s had already covered a distance of 10 m. if it has a constant acceleration of 2 m/s², find the position of the boy at the end of 5s.

Answer 1

The position of the boy at the end of 5 seconds is 45 meters.

Step-by-step explanation:

To find the position of the boy at the end of 5 seconds, we need to use the equation:x = xo + vot + (1/2)at²

where:

• x is the final position
• xo is the initial position
• vo is the initial velocity
• a is the acceleration
• t is the time

Substituting the given values, we get:

x = 10 + (2)(5) + (1/2)(2)(5)²

x = 10 + 10 + 25

x = 45 meters

Answer 2

To find the boy's position at the end of 5 seconds, we used the kinematic equation for motion with constant acceleration, resulting in a total distance of 45 meters from the starting point.

Step-by-step explanation:

The student's question involves calculating the position of the boy at the end of a 5-second interval, given his initial velocity and constant acceleration. In physics, motion with constant acceleration is described using kinematic equations. To find the position, we will use the following kinematic equation:
S = ut + (1/2)at2

Where:

• S is the displacement
• u is the initial velocity
• a is the acceleration
• t is the time

Given:

• Initial velocity, u = 2 m/s
• Constant acceleration, a = 2 m/s2
• Time, t = 5 s

Calculating the displacement:

S = (2 m/s)(5 s) + (1/2)(2 m/s2)(5 s)2
S = 10 m + 25 m
S = 35 m

Since the boy had already covered a distance of 10 m before this, the total distance covered (position of the boy) at the end of 5 seconds is:
Total distance = Initial distance + Displacement
Total distance = 10 m + 35 m
Total distance = 45 m

Therefore, the boy's position at the end of 5 seconds is 45 meters from the starting point.