Final answer:
To find the molarity of the 95% concentrated sulfuric acid solution, divide the moles of H2SO4 by the volume of the solution in liters.
Step-by-step explanation:
To find the molarity of the 95% concentrated sulfuric acid solution, we first need to calculate the amount of H2SO4 present in the solution. We can assume a 100g sample of the solution. From the given information, we know that the solution contains 95g of H2SO4 per 100g of solution. Therefore, in a 1000g (1kg) sample of the solution, there would be 950g of H2SO4.
Next, we need to convert the mass of H2SO4 to moles. The molar mass of H2SO4 is 98.09 g/mol. So, the moles of H2SO4 in 950g can be calculated by dividing the mass by the molar mass:
Moles of H2SO4 = 950g / 98.09 g/mol = 9.69 mol
Finally, to find the molarity of the solution, we need to divide the moles of H2SO4 by the volume of the solution in liters. The density of the solution is given as 1.834g/cm³, which is equivalent to 1.834g/mL or 1834g/L.
Molarity of the solution = Moles of H2SO4 / Volume of solution in liters = 9.69 mol / 1.834 L = 5.29 M