128k views
5 votes
A ball of mass m approaches a wall of mass M( >>m ) with a speed 4ms⁻¹ along the normal to the wall. The speed of the wall is 1ms−1 towards the ball. Find the speed of the ball after an elastic collision with the wall.

A. 5ms⁻¹ away from the wall
B. 3ms⁻¹ away from the wall
C. 9ms⁻¹ away from the wall
D. 6ms⁻¹ away from the wall

1 Answer

1 vote

Final answer:

In an elastic collision between a ball and a wall, the ball's final velocity is equal to the negative of its initial velocity. Therefore, the speed of the ball after the collision with the wall is 4 m/s away from the wall. Therefore, the correct answer is option A. 5 m/s away from the wall.

Step-by-step explanation:

In an elastic collision between a ball and a wall, both the momentum and the kinetic energy are conserved.

Let's denote the initial velocity of the ball as V1 and the final velocity as V2. Since the ball is moving along the normal to the wall, the velocity of the wall doesn't affect the collision. Therefore, we can consider the wall as stationary.

Using the conservation of momentum, we can set up the equation: m * V1 = m * V2

Since the mass of the ball is small compared to the mass of the wall, we can assume that the wall is immovable, and the mass of the wall doesn't affect the equation. Therefore, the final velocity of the ball after the collision is equal to the negative of its initial velocity: V2 = -V1.

Given that V1 = 4 m/s, the speed of the ball after the elastic collision with the wall is 4 m/s in the opposite direction, away from the wall. Therefore, the correct answer is option A. 5 m/s away from the wall.

User PrimaryChicken
by
8.7k points