Final answer:
In the single replacement reaction between lithium bromide and fluorine, fluorine would replace bromine due to its higher reactivity in the halogen group, leading to the formation of lithium fluoride and bromine gas.
Step-by-step explanation:
In a single replacement reaction between lithium bromide (LBr) and fluorine gas (F2), fluorine will replace bromine, because fluorine is the most reactive halogen. This is due to the reactivity trend within the halogen group (group 17 of the periodic table) where reactivity decreases from top to bottom.
Since fluorine is at the top of this group, it is more reactive than bromine, and can displace it from its compound. Therefore, in the provided equation 2LBr(aq) + F2(g) → 2Li(s) + 2FBr(g), the correct products would be lithium fluoride (LiF) and bromine gas (Br2), and the balanced reaction should be written as 2LBr(aq) + F2(g) → 2LiF(aq) + Br2(g).