Question

At what temperature in K will 0.930 moles of oxygen gas occupy 9.00 L and exert 2.80 atm of pressure?

Use R=0.08206L atmmol K for the gas constant.
Report your answer using three significant figures.

Answer 1

To calculate the temperature in K for 0.930 moles of oxygen at 2.80 atm and 9.00 L, use the ideal gas law (PV=nRT) and solve for T, ensuring to express the result with three significant figures.

Step-by-step explanation:

To find the temperature in kelvin at which 0.930 moles of oxygen gas will occupy 9.00 L and exert 2.80 atm of pressure, we use the ideal gas law which is PV = nRT. Here, P is the pressure in atmospheres (atm), V is the volume in liters (L), n is the number of moles of the gas, R is the ideal gas constant (0.0821 L.atm/mol.K), and T is the temperature in kelvin (K).

First, rearrange the ideal gas law to solve for T:

T = PV/(nR)

Substitute the given values into this equation:

T = (2.80 atm × 9.00 L) / (0.930 moles × 0.0821 L.atm/mol.K)

Calculating this, you will find the temperature T in kelvins. Make sure your final answer has three significant figures.