Question

4Al+3O₂--->2Al₂O₃

What is the theoretical yield of aluminum oxide if 1.80molof aluminum metal is exposed to 1.65molof oxygen?
In Part A, we saw that the theoretical yield of aluminum oxide is 0.90mol. Calculate the percent yield if the actual yield of aluminum oxide is 0.423mol.

Answer 1

The percent yield of aluminum oxide in this reaction is 47%.

Step-by-step explanation:

To calculate the percent yield in this reaction, we need to compare the actual yield to the theoretical yield. The theoretical yield is the amount of product that would be produced if the reaction went to completion, whereas the actual yield is the amount of product that was actually obtained in the experiment.

In this case, the theoretical yield of aluminum oxide is given as 0.90 mol. The actual yield is given as 0.423 mol. To calculate the percent yield, we can use the formula:

Percent Yield = (Actual Yield / Theoretical Yield) x 100%.

Plugging in the values, we get:

Percent Yield = (0.423 mol / 0.90 mol) x 100% = 47%.

Therefore, the percent yield of aluminum oxide in this reaction is 47%.