Final answer:
To make a 0.20 M solution of Cl-, you would need to use 33 mL of 6.0 M HCl.
Step-by-step explanation:
To determine the volume of 6.0 M HCl needed to make a 0.20 M solution of Cl-, you can use the equation
(M₁)(V₁) = (M₂)(V₂)
Where M₁ is the initial molarity, V₁ is the initial volume, M₂ is the final molarity, and V₂ is the final volume.
In this case, you know that M₂ = 0.20 M and V₂ = 1.00 L. To find V₁ (the volume of 6.0 M HCl), you can rearrange the equation to:
(6.0 M)(V₁) = (0.20 M)(1.00 L)
Simplifying, you find:
V₁ = (0.20 M)(1.00 L) / (6.0 M) = 0.033 L = 33 mL