Question

Which of the following opens the employee.txt file for output, creates a StreamWriter object, and assigns it to the outFile variable?

a. outFile = File.CreateText("F: \ employee.txt")
b. outFile = IO.File.CreateText("F: \employee.txt")
c. outFile = File.CreateText ( "F:\'") o
d. outFile = IO. File.Create("F: \ lemployee.txt")

Answer 1

The correct way to open an employee.txt file for output and create a StreamWriter object assigned to the outFile variable is using 'outFile = IO.File.CreateText("F:\\employee.txt")'. option b. `outFile = IO.File.CreateText("F:\employee.txt")`

Step-by-step explanation:

The question is asking how to open an employee.txt file for writing (output) and create a StreamWriter object assigned to the outFile variable in a .NET programming environment. The correct answer is option b: outFile = IO.File.CreateText("F:\employee.txt").

This line of code uses the CreateText method of the File class, which is part of the System.IO namespace, to create a new StreamWriter that writes to the employee.txt file. It is important to note the usage of the backslash (\) as an escape character for the file path.

The correct option for opening the "employee.txt" file for output, creating a StreamWriter object, and assigning it to the `outFile` variable is:

b. `outFile = IO.File.CreateText("F:\employee.txt")`

This option uses the correct syntax for creating a StreamWriter object in the context of VB.NET. It specifies the correct file path and utilizes the `CreateText` method from the `File` class in the `IO` namespace. The other options contain syntax errors, incorrect method names, or unnecessary characters that would prevent successful file creation and StreamWriter assignment in VB.NET.