Final answer:
At time t = 0s, as no discharging has taken place yet, the voltage across the capacitor is equal to the initial voltage, which is 12V.
Step-by-step explanation:
The voltage across a capacitor as it is discharging is described by an exponential function. At t = 0s, the potential across the capacitor is at its initial value Vo because no discharging has occurred yet.
Given that RC = 10s and the initial maximum potential (emf) is 12V, we can use the formula V = Voe-t/RC, where Vo is the initial voltage and t is the time. Plugging in the values, we find that the electric potential at t = 0s is simply the initial voltage, which is 12V.