Final answer:
To express the integral of the function f(x) = x^3 - 4x from 0 to 3 as a limit of a Riemann sum, we partition the interval [0,3] into n equal-width parts and as n approaches infinity, the Riemann sum converges to the value of the integral.
Step-by-step explanation:
To express the integral of the function f(x) = x³ - 4x from 0 to 3 using a Riemann sum, we first define the interval [0,3] to be subdivided into n equal-width partitions. The width of each subinterval, Δx, is ³/n. Letting xi denote the right endpoint of the i-th subinterval, we have xi = (i³)/n. The Riemann sum can then be represented as:
Σi=1^n f(xi)Δx
Substituting in the expression for f(xi) and Δx, we get:
Σi=1^n [(i³/n)³ - 4(i³/n)](³/n).
As the number of subintervals n goes to infinity, the Riemann sum approaches the exact value of the integral:
∑ n → ∞ Σi=1^n [(i³/n)³ - 4(i³/n)](³/n)