Question

Consider the following Boolean expression in which the int variables x and y have been properly declared and initialized.

(x >=10) == (y < 12)

Which of the following values for x and y will result in the expression evaluating to true?

O x = 10 and y = 12
O x = 9 and y = 9
O x = 10 and y = 11
O x = 10 and y = 13
O x = 9 and y = 12

Answer 1

The values for x = 10 and y = 11 will result in the expression evaluating to true.

Let's break down the expression:

(x >= 10) == (y < 12)

This expression compares two Boolean value

(x >= 10): This checks if the value of x is greater than or equal to 10.

(y < 12): This checks if the value of y is less than 12.

It then compares these two conditions using the == operator, which checks if both sides are equal.

Let's evaluate the given options:

x = 10 and y = 12

For this set of values, (x >= 10) is true because 10 is equal to 10, and (y < 12) is false because 12 is not less than 12. This would result in (true) == (false) which is false.

x = 9 and y = 9

(x >= 10) is false because 9 is not greater than or equal to 10, and (y < 12) is true because 9 is less than 12. This would result in (false) == (true) which is false.

x = 10 and y = 11

(x >= 10) is true because 10 is equal to 10, and (y < 12) is true because 11 is less than 12. This would result in (true) == (true) which is true.

x = 10 and y = 13

(x >= 10) is true because 10 is equal to 10, but (y < 12) is false because 13 is not less than 12. This would result in (true) == (false) which is false.

x = 9 and y = 12

(x >= 10) is false because 9 is not greater than or equal to 10, and (y < 12) is false because 12 is not less than 12. This would result in (false) == (false) which is true.

So, the values for x = 10 and y = 11 will result in the expression evaluating to true.