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A 27.00 mL sample of an unknown H₃PO₄ solution is titrated with a 0.110 M NaOH solution. The equivalence point is reached when 28.08 mL of NaOH solution is added.

The neutralization reaction is
H₃PO₄(aq)+3NaOH(aq)→3H₂O(l)+Na₃PO₄(aq)
What is the concentration of the unknown H₃PO₄ solution?

User Enchew
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Final answer:

To find the concentration of the H₃PO₄ solution, calculate the moles of NaOH used at the equivalence point, use the stoichiometry of the reaction to find the moles of H₃PO₄, and then divide by the volume of the H₃PO₄ solution. The concentration is found to be 0.03813 M.

Step-by-step explanation:

To determine the concentration of the unknown H₃PO₄ solution, we can use the data from the titration with a known concentration of NaOH solution.

Since the neutralization reaction H₃PO₄(aq) + 3NaOH(aq) → 3H₂O(l) + Na₃PO₄(aq) involves three moles of NaOH for every mole of H₃PO₄, we can calculate the moles of NaOH used at the equivalence point and then determine the moles of H₃PO₄.

First, we calculate the number of moles of NaOH: (0.02808 L NaOH) × (0.110 M NaOH) = 0.0030888 moles of NaOH.

Since it takes 3 moles of NaOH to neutralize 1 mole of H₃PO₄, the moles of H₃PO₄ will be a third of the moles of NaOH: 0.0030888 moles NaOH ÷ 3 = 0.0010296 moles H₃PO₄.

Finally, to find the concentration of H₃PO₄, we divide the moles of H₃PO₄ by the volume of the H₃PO₄ solution in liters:

Concentration of H₃PO₄= 0.0010296 moles ÷ 0.02700 L

= 0.03813 M.

Therefore, the concentration of the unknown H₃PO₄ solution is 0.03813 M.

User Jannis Defu
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