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Cl₂​(g)+2HCl−(aq) has a larger reduction half potential than Br₂​(g)+2e−⇌2Br−(aq) If these are combined to make a galvanic cell, match the types of agents:

A) Oxidizing agent
B) Reducing agent

User Eric Hill
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Final answer:

Cl₂ functions as the oxidizing agent by being reduced, and Br⁻ serves as the reducing agent by being oxidized in the galvanic cell.

Step-by-step explanation:

In a galvanic cell combining the two half-reactions Cl₂ (g) + 2e⁻ → 2Cl⁻ (aq) and 2Br⁻ (aq) → Br₂ (g) + 2e⁻, chlorine gas (Cl₂) is being reduced and thus serves as the oxidizing agent.

On the other hand, bromide ions (Br⁻) are being oxidized to form bromine gas (Br₂), which means that Br⁻ is the reducing agent. The heavier halide ions, such as Cl⁻ and Br⁻, typically act as reducing agents, while lighter halogens or other oxidizing agents will oxidize them. The standard reduction potentials indicate which species is a better oxidant or reductant in an electrochemical cell.

User Geasi Puozzo
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