Final answer:
Cl₂ functions as the oxidizing agent by being reduced, and Br⁻ serves as the reducing agent by being oxidized in the galvanic cell.
Step-by-step explanation:
In a galvanic cell combining the two half-reactions Cl₂ (g) + 2e⁻ → 2Cl⁻ (aq) and 2Br⁻ (aq) → Br₂ (g) + 2e⁻, chlorine gas (Cl₂) is being reduced and thus serves as the oxidizing agent.
On the other hand, bromide ions (Br⁻) are being oxidized to form bromine gas (Br₂), which means that Br⁻ is the reducing agent. The heavier halide ions, such as Cl⁻ and Br⁻, typically act as reducing agents, while lighter halogens or other oxidizing agents will oxidize them. The standard reduction potentials indicate which species is a better oxidant or reductant in an electrochemical cell.