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F(x)=x^2-4x-8 find the zeros

User Aadlc
by
8.5k points

1 Answer

2 votes

Answer:

x = 2 ± 2√3

Explanation:

f(x) = x² − 4x − 8

Use quadratic formula:

x = [ -b ± √(b² − 4ac) ] / 2a

x = [ -(-4) ± √((-4)² − 4(1)(-8)) ] / 2(1)

x = [ 4 ± √(16 + 32) ] / 2

x = (4 ± √48) / 2

x = (4 ± 4√3) / 2

x = 2 ± 2√3

User Bennett Keller
by
8.2k points

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