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Draw the Lewis dot structure of the molecule IF5 and determine the electron and molecular geometries around the I atom.

User Czimi
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Final answer:

The Lewis dot structure of IF5 is determined by considering the valence electrons of each atom. The electron geometry around the I atom is trigonal bipyramidal, and the molecular geometry around the I atom is square pyramidal.

Step-by-step explanation:

The Lewis dot structure of the molecule IF5 can be determined by considering the valence electrons of each atom. Iodine (I) has 7 valence electrons, and since there are 5 fluorine atoms (F) surrounding the iodine, the total number of valence electrons in IF5 is 7 + (5 x 7) = 42.

In the Lewis structure, the I atom is placed centrally, with the 5 F atoms surrounding it. Each F atom is bonded to the I atom through a single bond, represented by a straight line connecting the atoms. The remaining 4 valence electrons of I are represented as lone pairs around the I atom.

The electron geometry around the I atom is trigonal bipyramidal, as it has 5 regions of electron density (bonding pairs and lone pairs). The molecular geometry around the I atom is square pyramidal, as there are 5 bonding pairs and 1 lone pair around the central I atom.

User JonB
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