Question

An oscillating LC circuit consisting of a 1.0 nF capacitor and a 3.7 mH coil has a maximum voltage of 2.6 V. What are (a) the maximum charge on the capacitor

Answer 1

The maximum charge on a 1.0 nF capacitor with a maximum voltage of 2.6 V is 2.6 nanoCoulombs (nC).

Step-by-step explanation:

The maximum charge on the capacitor in an oscillating LC circuit can be found by recognizing that the maximum voltage across the capacitor is equivalent to when the capacitor holds the maximum charge (Qmax). This is described by the equation Qmax = C * Vmax, where C is the capacitance and Vmax is the maximum voltage across the capacitor. For a capacitor with 1.0 nF (nanoFarads) capacitance and a maximum voltage of 2.6 V, the maximum charge (Qmax) can be calculated as follows:

Qmax = C * Vmax
Qmax = 1.0 * 10-9 F * 2.6 V

Qmax = 2.6 * 10-9 C

Therefore, the maximum charge on the capacitor is 2.6 nanoCoulombs (nC).