Question

X^4-12x^2+32=0 find all roots

Answer 1

The roots of the equation x^4-12x^2+32=0 are x = ±2 and x = ±2√2.

Step-by-step explanation:

To find the roots of the equation x^4-12x^2+32=0, we can use factoring and the quadratic equation.

Let's start by factoring this equation:

x^4-12x^2+32 = (x^2-4)(x^2-8)

Now, set each factor equal to zero:

x^2-4 = 0

=> x^2 = 4

=> x = ±2

x^2-8 = 0

=> x^2 = 8

=> x = ±√8

= ±2√2

Therefore, the roots of the equation are x = ±2 and x = ±2√2.