Question

calculate the rotational inertia of a meter stick, with mass 0.56kg, about an axis perpendicular to the stick and located at the 20cm

Answer 1

The rotational inertia of a meter stick can be calculated using the formula I = (1/3) * M * L^2, where I is the rotational inertia, M is the mass of the meter stick, and L is the length of the meter stick. In this case, the mass of the meter stick is 0.56 kg and the length of the meter stick is 1 meter (100 cm). Therefore, the rotational inertia can be calculated as I = (1/3) * 0.56 kg * (100 cm)^2.

Step-by-step explanation:

The rotational inertia of a meter stick can be calculated using the formula:

I = (1/3) * M * L^2

where I is the rotational inertia, M is the mass of the meter stick, and L is the length of the meter stick.

In this case, the mass of the meter stick is 0.56 kg and the length of the meter stick is 1 meter (100 cm). Therefore, the rotational inertia can be calculated as:

I = (1/3) * 0.56 kg * (100 cm)^2

Simplifying this equation gives:

I = (1/3) * 0.56 kg * 10000 cm^2

I = 1866.67 kg cm^2