Question

calculate the molarity of a solution that has a total volume of 182.0 ml and contains 14.90 g of aluminum chloride

Answer 1

To calculate the molarity, convert the mass of aluminum chloride (14.90 g) to moles using the molar mass, convert the volume of the solution to liters, and divide moles by liters, resulting in approximately 0.6143 M for the solution.

Step-by-step explanation:

To calculate the molarity of a solution, you need to know two things:

1. The number of moles of solute present in the solution.
2. The volume of the solution in liters.

Here are the steps we're going to follow to find the molarity of aluminum chloride solution:

1. Calculate the number of moles of AlCl3 using its molar mass.
2. Convert the volume of the solution from milliliters to liters.
3. Divide the number of moles of AlCl3 by the volume of the solution in liters.

The molar mass of AlCl3 is 133.33 g/mol. To convert the mass of AlCl3 (14.90 g) to moles, we divide by the molar mass:

moles of AlCl3 = 14.90 g / 133.33 g/mol

This results in approximately 0.1117 moles of AlCl3.

Next, convert the volume of the solution to liters:

182.0 mL = 0.1820 L

Now, calculate the molarity (M):

M = moles of solute / liters of solution

M = 0.1117 moles / 0.1820 L

M = approximately 0.6143 M