Final answer:
Using the ideal gas law and substituting the given values, the temperature of the 150-g mass of krypton at a pressure of 210 kPa and volume of 15.0 L is approximately 223.3 Kelvin.
Step-by-step explanation:
To find the temperature of a 150-g mass of krypton that occupies 15.0 L at a pressure of 210 kPa, we can use the ideal gas equation: PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature in Kelvin.
First, we calculate the number of moles (n) of krypton using its mass (m) and molar mass (M):
n = m / M = 150 g / 83.8 g/mol ≈ 1.789 moles
Next, we substitute the values into the ideal gas equation, solving for T:
PV = nRT ⇒ T = PV / (nR)
We use the value of R when the pressure is in kPa, which is 8.314 (L·kPa)/(K·mol).
T = (210 kPa) (15.0 L) / (1.789 moles) (8.314 L·kPa/K·mol)
T ≈ 223.3 K
Therefore, the temperature of the krypton gas under the given conditions is approximately 223.3 Kelvin.