The linear relationship between demand (x) and price per pound (y) is expressed as y = -0.15x + 11.5. Predicting the demand when the price is $5.80 per pound yields approximately 38 pounds.
To express the price as a function of demand in a linear relationship, we can use the point-slope form of a linear equation:
![\[ y - y_1 = m(x - x_1) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/c43lppso0e9zjavshclm60ubvbni34e6n2.png)
In this case, let x represent the demand in pounds and y represent the price per pound. We have two points: (50, 4) and (40, 5.5).
Let's calculate the slope m:
![\[ m = (y_2 - y_1)/(x_2 - x_1) \]\[ m = (5.5 - 4)/(40 - 50) \]\[ m = (1.5)/(-10) = -0.15 \]](https://img.qammunity.org/2024/formulas/business/high-school/iedfzvs9b1tnnpf4hk25p5vs3njfqgkhic.png)
Now, we can use the point-slope form with one of the points. Let's use (50, 4):
y - 4 = -0.15(x - 50)
Now, solve for y to express the price as a function of demand:
y = -0.15x + 11.5
So, the price per pound y as a function of demand x is y = -0.15x + 11.5.
Now, to predict the demand x if the price rises to $5.80 per pound, we can set y = 5.80 and solve for x:
![\[ 5.80 = -0.15x + 11.5 \]](https://img.qammunity.org/2024/formulas/business/high-school/pbxizs7sszng5xgx7fhhwyfrh440si5f75.png)
Subtract 11.5 from both sides:
![\[ -5.70 = -0.15x \]](https://img.qammunity.org/2024/formulas/business/high-school/ddam0cji0dn7nviz9qmb7wst5n6g5gu9qi.png)
Divide both sides by -0.15:
![\[ x = (-5.70)/(-0.15) \]\[ x = 38 \]](https://img.qammunity.org/2024/formulas/business/high-school/8gbl21xcx5ssrd6353sjt0pdtvo3lwlnyi.png)
Therefore, the predicted demand, when the price rises to $5.80 per pound, is approximately 38 pounds.