Final answer:
The inductive reactance of a 74.0 mH inductor connected to a 106.0 Hz AC source is approximately 49.172 Ω.
Step-by-step explanation:
The question involves calculating the inductive reactance of an inductor in an AC circuit which is given by the formula Χ_L = 2πfL, where Χ_L is the inductive reactance, f is the frequency of the AC source, and L is the inductance of the coil.
Using this formula, we can find the inductive reactance for a 74.0 mH inductor connected to a 106.0 Hz AC source. The calculation is as follows:
Χ_L = 2π * 106.0 Hz * 74.0×10⁻³ H
Χ_L = 2π * 106.0 * 0.074 Ω
Χ_L = 49.172 Ohms