Question

a class, which implements an interface, does not override a method in the interface and does not causes errors when it is compiled because the method is a_________method.

Answer 1

When a class does not override a method in an interface and does not cause errors when compiled, it is because the method is abstract.

Step-by-step explanation:

In the context of an interface, when a class does not override a method in the interface and does not cause errors when it is compiled, it is because the method is an abstract method. An abstract method is a method that is declared in an interface but does not provide any implementation. It is up to the class that implements the interface to provide the implementation of the abstract method.

For example, let's say we have an interface called 'Shape' with an abstract method called 'calculateArea()'. If a class 'Rectangle' implements the 'Shape' interface but does not override the 'calculateArea()' method, the class 'Rectangle' will need to be declared as abstract:

public abstract class Rectangle implements Shape { }

This indicates that the class 'Rectangle' does not provide the implementation for the 'calculateArea()' method, and it is up to any concrete subclass of 'Rectangle' to provide the implementation.