Question

What is the result when the right hand side of the equation below

√√x+6=4-√√2-x
16-8√ √2-x+2-x
016-(2-x)
16-√2-x
16-2√√ 2-x+2−x

Answer 1

To solve the equation √√x+6=4-√√2-x, we can square both sides of the equation, expand and simplify to collect like terms, and then rearrange the equation to isolate x.

option b is the correct

Step-by-step explanation:

To solve the equation √√x+6=4-√√2-x, we need to isolate the square root terms. First, we square both sides of the equation to get rid of the square roots. This gives us (√x+6)² = (4-√√2-x)².

Next, we expand both sides of the equation, simplify, and collect like terms. This gives us x + 12√x + 36 = 16 - 8√√2-x + 2 - x.

Finally, we rearrange the equation and solve for x by moving all terms with x to one side of the equation and simplifying. The result is x = 16 - 8√√2-x + 2 - 36 - 12√x.