Question

of an organic substance was heated in a carius tube and the sulphuric acid formed was precipitated asbaso4 with BaCl₂ . the weight of the dry BaSO₄ was 0.35 g. the of sulphur in the compound is:

Answer 1

The mass percent of sulfur cannot be calculated without the mass of the original organic compound, which is not provided. However, if known, it is calculated by dividing the mass of sulfur (0.0481 g as derived from the 0.35 g of BaSO4) by the mass of the original sample and multiplying by 100%.

Step-by-step explanation:

To determine the percentage of sulfur in the organic compound, we will use gravimetric analysis principles. Given the precipitated mass of BaSO4 is 0.35 g, we need to find the amount of sulfur that corresponds to this mass. We start with the molar mass of BaSO4, which is 233.43 g/mol.

The stoichiometry of the reaction indicates that each mole of BaSO4 contains one mole of sulfur. Using the molar mass of sulfur (32.07 g/mol), we can calculate the mass of sulfur:

• mass of S = (mass of BaSO4 / molar mass of BaSO4) × molar mass of S
• mass of S = (0.35 g / 233.43 g/mol) × 32.07 g/mol
• mass of S = 0.0481 g

The mass percent of sulfur in the original compound would then be the mass of sulfur divided by the mass of the original sample, multiplied by 100:

mass percent S = (mass of S / mass of original sample) × 100%

However, as the mass of the original organic compound is not provided in the question, we cannot calculate the exact percentage of sulfur without this information.