Question

Plane wavefront of light of wavelength 6000A° is incident on two slits on a screen perpendicular to the direction of light rays. If the total separation of 10 bright fringes on a screen 2 m away is 2 cm, find the distance between the slits.

Answer 1

The distance between the slits is 300,000 nm/m.

Step-by-step explanation:

Given:
Wavelength of light (λ) = 6000 Å = 600 nm
Distance between screen and fringes (L) = 2 m
Total separation of 10 bright fringes (x) = 2 cm
Let d be the distance between the slits. Using the formula for fringe separation in a double slit experiment, we have:
x = λL/d
Plugging in the given values, we can solve for d:
d = λL/x = 600 nm * 2 m / 2 cm = 6000 nm / 0.02 m = 300000 nm / m