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an iron rod 1.8 cm diameter is bent to form a ring of mean diameter 25cm andwound with 250 turn of wire. a gap of 1mm exists in between the end faces.calculate the current required to produce a flux of 0.6mwb. take relativepermeability of iron as 1200

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Final answer:

The question concerns the calculation of current required to produce a particular magnetic flux in an iron-core toroid. To find the current, we use the formula for magnetic flux in a toroid, taking into account the dimensions of the ring, the relative permeability, and the gap in the iron core.

Step-by-step explanation:

The student is asking about the amount of current required to produce a specified magnetic flux in a ring formed by bending an iron rod and winding it with a coil of wire. Given the ring's dimensions, the relative permeability of iron, and the number of turns in the wire, we must apply the formula for magnetic flux (Φ) in a toroidal core, which is Φ = (NIμμ0·A) / L, where N is the number of turns, I is the current, μ is the relative permeability, μ0 is the permeability of free space, A is the cross-sectional area, and L is the magnetic path length. Considering the gap in the ring, the effective magnetic length will be slightly longer than the circumference of the ring.

In order to find the current (I) required, we will rearrange the formula to solve for I: I = ΦL / (Nμμ0·A). We'll use the given relative permeability of iron (μ = 1200), the number of turns (N = 250), the diameter of the rod to calculate cross-sectional area (A), and calculate the magnetic path length (L) using the mean diameter of the ring (25 cm) while accounting for the 1 mm gap. The permeability of free space (μ0) is a constant, approximately 4π x 10-7 H/m.

Using these values, we can determine the necessary current to achieve the specified 0.6 mWB (milliweber) flux. This will involve converting all dimensions to meters, ensuring consistency in the units used.

User Joel Cunningham
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