Question

the triangular side walls of a flyover have been used for advertisements. the sides of the walls are 13 m, 14 m and 15 m. the advertisements yield an earning of rs 2000 per m² a year. a company hired one of its walls for 6 months. how much rent did it pay?

Answer 1

The company paid Rs 44900 as rent for renting one wall of the flyover for 6 months.

Step-by-step explanation:

To find the area of the triangular side walls, we can use Heron's formula, which is given by:

A = sqrt(s(s-a)(s-b)(s-c))

Where A is the area of the triangle and s is the semiperimeter of the triangle.

Substituting the given values, we have:

A = sqrt(21(21-13)(21-14)(21-15))

Simplifying, we get:

A = sqrt(21 * 8 * 7 * 6)

A = sqrt(2016)

A ≈ 44.9 m²

The rent paid by the company can be calculated by multiplying the area of the wall by the rate per square meter per year:

Rent = Area * Rate

Since the company rented the wall for 6 months, we need to divide the calculated rent by 2:

Rent = (Area * Rate) / 2

Substituting the values, we have:

Rent = (44.9 * 2000) / 2

Rent ≈ 44900 Rs