Final answer:
The team should choose the combination of stories that maximizes their capacity without exceeding it. Without the capacity provided, the best guess is to assume their limit is 8 points, in which case the correct answer is Option A: Stories 1, 2 and 4 Option A is correct.
Step-by-step explanation:
To determine which stories the team should include in iteration one, it is essential to consider the total number of story points that the team can complete in that iteration. Unfortunately, the total capacity for iteration one is not provided in the question.
Assuming the team has a capacity greater than or equal to 8 points, the combination of stories that maximizes the use of their capacity without exceeding it would be optimal.
Therefore, looking at the story points for each story:
Story 3: 3 story points
Stories 1 and 2 and 4 (totaling 8 story points)
Since option B (Stories 1, 3, and 4) exceeds the 8-point limit (with a total of 9 points), it should be excluded. Options A and C are both viable, but option A (Stories 1, 2, 4) uses the full capacity if we assume the team can take on 8 points. Thus, the correct answer is most likely Option A: Stories 1, 2, and 4.