Final answer:
Creating a C++ program that calculates voltage values using Ohm's Law and displays the results, utilizing arrays and pointers for array element access.
Step-by-step explanation:
To address the student's query, a C++ program can be written that includes three one-dimensional arrays for 'current', 'resistance', and 'voltage'. The program will have a 'calcVolts()' function that takes the 'current' and 'resistance' arrays, calculates the 'voltage' using Ohm's Law (V = I * R), and stores it in the voltage array utilizing pointer arithmetic to access the array elements.
Here's an example of how the C++ function calcVolts() would look:
void calcVolts(double current, double* resistance, double voltage, int size) {
for(int i = 0; i < size; ++i) {
*(voltage + i) = *(current + i) * *(resistance + i);
}
}
And to display the values within the main function after calculation:
int main() {
double current[10] = {10.62, 14.89, 13.21, 16.55, 18.62, 9.47, 6.58, 18.32, 12.15, 3.98};
double resistance[10] = {4, 8.5, 6, 7.35, 9, 15.3, 3, 5.4, 2.9, 4.8};
double voltage[10];
calcVolts(current, resistance, voltage, 10);
for(int i = 0; i < 10; ++i) {
cout << "Voltage[" << i << "]: " << voltage[i] << endl;
}
return 0;
}
The program successfully calculates and displays the voltages based on the given current and resistance values using pointers, demonstrating the use of functions and arrays in C programming.