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a population has a gene with 2 alleles, f and f. the frequency of the f allele is 0.8. the frequency of the f allele is 0.2. this is all that you know about this population. what is the frequency of the ff genotype?

User Jason Renaldo
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2 Answers

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22 votes

Final answer:

The frequency of the ff genotype in the population, calculated using the Hardy-Weinberg principle, is 0.04 or 4%.

Step-by-step explanation:

To calculate the frequency of the ff genotype, we use the Hardy-Weinberg principle which states that the frequency of genotypes in a population can be represented as p² + 2pq + q² = 1, where p is the frequency of one allele (in this case, f), and q is the frequency of the other allele (in this case, f). Given that the frequency of the f allele (p) is 0.8 and the frequency of the f allele (q) is 0.2, we can calculate the frequency of the ff genotype (q²) as follows:

q² = (0.2)²

q² = 0.04

Therefore, the frequency of the ff genotype is 0.04 or 4%.

User Rzysia
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7 votes
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Answer: answer below

Explanation: Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals. The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 peopleHeterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150 --> 48 peopleAnd homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 peopleHope that helps you to understand how to solve these types of population genetics problems!

User Master Yoda
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