Question

Use the frequency distribution to complete parts (a) through (e)

a) Determine the total number of observations.
b) Determine the width of each class.
c) Determine the midpoint of the second class.
d) Determine the modal class (or classes).
e) Determine the class limits of the next class if an additional class were to be added.

Class Frequency
6 - 15 4
16 - 25 8
26 - 35 8
36 - 45 9
46 - 55 3
56 - 65 3

a) The total number of observations is ______.
b) The width of each class is ______.
c) The midpoint of the second class is ______.(Type an integer or a decimal.)
d) The modal class(es) is/are ______. (Use a hyphen to separate the limits of a class. Use a comma to separate answers.

Answer 1

To analyze the frequency distribution, we find the total observations (35), class width (9), midpoint of the second class (20.5), modal class (36 - 45), and class limits for an additional class (66 - 75).

Step-by-step explanation:

To analyze the given frequency distribution, we start by addressing each part of the question sequentially:

1. Total number of observations: To find this, add up all the frequencies: 4 + 8 + 8 + 9 + 3 + 3 = 35.
   
   
2. Width of each class: Subtract the lower limit of the first class from the upper limit of the same class. For 6 - 15, it would be 15 - 6 = 9. Since the classes are consistent, this width applies to all other classes.
   
   
3. Midpoint of the second class: The midpoint is calculated by adding the lower and upper limits of the class and dividing by 2. So, for 16 - 25, midpoint = (16 + 25) / 2 = 20.5.
   
   
4. Modal class: This is the class with the highest frequency, which is 36 - 45 with a frequency of 9.
   
   
5. Class limits of the next class: If we continue with the same class width of 9, and the last class was 56 - 65, the next one would be 66 - 75.