Final answer:
The resonant frequency of the parallel resonant circuit is approximately 1.19 MHz.
The quality factor of the circuit is approximately 37.42 kHz.
The bandwidth of the circuit is approximately 31.84.
Step-by-step explanation:
The resonant frequency (f₀) of a parallel resonant circuit can be found using the formula:
f₀ = 1 / (2π√(LC))
Where L is the inductance and C is the capacitance. Substituting the values, we get:
f₀ = 1 / (2π√(50µH * 600pF))
f₀ ≈ 1.19 MHz
The quality factor (Q) of the circuit can be found using the formula:
Q = R * √(C / L)
Substituting the values, we get:
Q = 7kΩ * √(600pF / 50µH)
Q ≈ 37.42 kHz
The bandwidth (B) of the circuit can be found using the formula:
B = f₀ / Q
Substituting the values, we get:
B = 1.19 MHz / 37.42 kHz
B ≈ 31.84