Question

a 100 v ac circuit with frequency 50 hz is applied across a resistance of 10 and capacitor of 500 μf. find current and phase difference between voltage and current. in an electric iron heat produced is same, whether it is connected across an a.c. source or across 50 v

Answer 1

The current is 8.32 A and the phase difference is 90 degrees.

Step-by-step explanation:

To find the current and phase difference between voltage and current in a 100 V AC circuit with a frequency of 50 Hz, we need to calculate the reactance of the capacitor and the impedance of the circuit.

The reactance of the capacitor can be calculated using the formula XC = 1 / (2πfC), where XC is the reactance, f is the frequency, and C is the capacitance.

Plugging in the values, we get XC = 1 / (2π * 50 * 500 * 10^-6)

= 6.37 Ω.

The impedance of the circuit is given by Z = √(R^2 + XC^2), where R is the resistance.

Plugging in the values, we get Z = √(10^2 + 6.37^2)

= 12.02 Ω.

Now, we can calculate the current using the formula I = V / Z, where V is the voltage.

Plugging in the values, we get I = 100 V / 12.02 Ω

= 8.32 A.

The phase difference between voltage and current in an AC circuit with a resistor and a capacitor is 90 degrees.