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a 100 gram rope is stretched downwards at a distance of l/3 from its first end, moving it perpendicularly by a length of l/30. if this displacement is reached in 1 second and is done with a constant acceleration of 3. calculate the wave equation if the rope is homogeneous with an elasticity coefficient of a?.

User Carlie
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Final answer:

The question relates to deriving a wave equation for a rope that is displaced with constant acceleration, but does not provide enough information to do so accurately. The wave speed on a string depends on its tension and linear mass density, which are not given. Therefore, a precise wave equation specific to the conditions described cannot be ascertained without further data.

Step-by-step explanation:

Wave Equation for a Stretched Rope

The student's question relates to the derivation of a wave equation for a rope under specific conditions. The rope is homogeneous with a known mass and elasticity coefficient and is displaced with a constant acceleration to reach a given displacement in a certain time.

To derive the wave equation, one would typically need to know the tension in the rope and its linear mass density. However, these details are not provided in the student's question. Instead, we are given the elasticity coefficient 'a' and acceleration, but this is not sufficient to derive a standard wave equation.

For the standard wave equation on a string, the wave speed 'v' is determined by the formula v = sqrt(T/μ), where 'T' is the tension in the string and 'μ' is the linear mass density. With the wave speed, the wave equation would normally take the form y(x, t) = A sin(kx - ωt + ϕ), where 'A' is the amplitude, 'k' is the wave number, 'ω' is the angular frequency, and 'ϕ' is the phase constant. The details provided in the question are insufficient to define a precise wave equation without additional context or assumptions.

User Jan Wielemaker
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