Question

a solenoid has a core of a material with relative permeability 400. the windings of the solenoid are insulated from the core and carry a current of 2a. if the number of turns is 1000 per meter, calculate a)h b)m c)b and d) the magnetizing current im?

Answer 1

To calculate the quantities for the solenoid, we need to use the formula for the magnetic field inside a solenoid. Using this formula, we can calculate the values for (a) B, (b) m, (c) b, and (d) im.

Step-by-step explanation:

In order to calculate the various quantities, we need to use the formula for the magnetic field inside a solenoid:

B = μ0 * n * I

where B is the magnetic field, μ0 is the permeability of free space, n is the number of turns per unit length, and I is the current.

Using this formula, we can calculate the values for (a) B, (b) m, (c) b, and (d) im as follows:

(a) B = μ0 * n * I = (4π x 10^-7 T m/A) * (1000 turns/m) * (2A) = 8π x 10^-4 T

(b) m = μr * m0 = 400 * (4π x 10^-7 T m/A) = 1.6π x 10^-4 T

(c) b = μr * B = 400 * (8π x 10^-4 T) = 3.2π x 10^-1 T

(d) im = (B - μ0) * A = (8π x 10^-4 T - 4π x 10^-7 T m/A) * (1 m^2) = 7.96π x 10^-4 T m2/A